Saturday 12 September 2015

`3^(x+4)=6^(2x-5)` Solve the equation.

`3^(x+4) = 6^(2x-5)`


To solve, take the natural logarithm of both sides.


`ln (3^(x+4)) = ln (6^(2x-5))`


To simplify each side, apply the logarithm rule `ln (a^m) =m*ln(a)` .


`(x+4)ln(3) = (2x-5) ln (6)`


`xln(3)+4ln(3) = 2xln(6) - 5ln(6)`


Then, bring together the terms with x on one side of the equation. Also, bring together the terms without x on the other side of the equation.


`xln(3) - 2xln(6) = -4ln(3) -5ln(6)`


At the left...

`3^(x+4) = 6^(2x-5)`


To solve, take the natural logarithm of both sides.


`ln (3^(x+4)) = ln (6^(2x-5))`


To simplify each side, apply the logarithm rule `ln (a^m) =m*ln(a)` .


`(x+4)ln(3) = (2x-5) ln (6)`


`xln(3)+4ln(3) = 2xln(6) - 5ln(6)`


Then, bring together the terms with x on one side of the equation. Also, bring together the terms without x on the other side of the equation.


`xln(3) - 2xln(6) = -4ln(3) -5ln(6)`


At the left side, factor out the GCF.


`x(ln(3) - 2ln(6)) =-4ln(3) -5ln(6)`


And, isolate the x.


`x = (-4ln(3) - 5ln(6))/(ln(3)-2ln(6))`


`x~~5.374`


Therefore, the solution is `x~~5.374` .

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