To find a tangent line to a polar curve, we regard
as parameter and write it's parametric equations as,
We are given the polar curve
Now let's convert polar equation into parametric equation,
Slope of the line tangent to the parametric curve is given by the derivative
Let's take the derivative of x and y with respect to
To find a tangent line to a polar curve, we regard
as parameter and write it's parametric equations as,
We are given the polar curve
Now let's convert polar equation into parametric equation,
Slope of the line tangent to the parametric curve is given by the derivative
Let's take the derivative of x and y with respect to
use the trigonometric identity:
Use the trigonometric identity:
We locate horizontal tangents by finding the points where ( provided that
)
and vertical tangents at the points where ( provided that
)
Setting the derivative of x equal to zero for locating vertical tangents,
Let's find the corresponding radius r for the above angles,
For
For
For
For
Now let's set the derivative of y equal to zero for locating horizontal tangents,
Now, find the corresponding radius r for above angles,
For
For
For
For
Note: If we plot the polar curve , its a circle and it should have two horizontal and two vertical tangents. However we got four points because it depends on a, whether it's positive or negative.
For positive value of a ,
the polar curve has horizontal tangents at
and vertical tangents at
For negative value of a,
the polar curve has horizontal tangents at
and vertical tangents at
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